Talk:Inductance
| This It is of interest to the following WikiProjects: | |||||||||||||||||||||
| |||||||||||||||||||||
| The content of Inductance with physical symmetry was merged into Inductance on 16 August 2012. The former page's history now serves to provide attribution for that content in the latter page, and it must not be deleted as long as the latter page exists. For the discussion at that location, see its talk page. |
| The content of Neumann formula was merged into Inductance. The former page's history now serves to provide attribution for that content in the latter page, and it must not be deleted as long as the latter page exists. For the discussion at that location, see its talk page. |
There is a recent edit mentioning Big O notation. It seems to me that some of the terms on the page actually need Little o notation, though. Gah4 (talk) 18:20, 15 October 2022 (UTC)
Nationality
editWhy introduce Henry as "American scientist Joseph Henry"? Why not just call him "Joseph Henry"? Is his nationality relevant? Why aren't Heaviside or Lenz introduced in terms of their nationalities? Gerardhiggins (talk) 15:33, 2 December 2022 (UTC)
Incorrect Diagram
editUnder section inductive reactance, the diagram shows the current leading by 90°, but in the caption we have The current lags the voltage by 90°, Which is actually correct, across an inductor the current does lag. Siddharthbhat02 (talk) 21:28, 12 June 2023 (UTC)
- @Chetvorno: The image does appear to show a leading current rather than a lagging current. Constant314 (talk) 22:22, 12 June 2023 (UTC)
- No, on the graph the first positive voltage peak occurs at 90° on the horizontal time axis, the first positive current peak occurs at 180°. Similarly the voltage line crosses the axis in a positive direction at 0°, while the current crosses it at 90°. The current lags the voltage.--ChetvornoTALK 14:23, 13 June 2023 (UTC)
- You are right, of course. I don't know what I was thinking.Constant314 (talk) 04:01, 13 June 2023 (UTC)
- No, on the graph the first positive voltage peak occurs at 90° on the horizontal time axis, the first positive current peak occurs at 180°. Similarly the voltage line crosses the axis in a positive direction at 0°, while the current crosses it at 90°. The current lags the voltage.--ChetvornoTALK 14:23, 13 June 2023 (UTC)
Wheeler's approximation formula for current-sheet
editWheeler's approximation formula for current-sheet was in inches. You cannot convert to cm by using the factor 2.5 without degrading the formula's 1% accuracy. Either use the correct factor 2.54, or alter the stated accuracy. 110.174.215.170 (talk) 15:57, 1 September 2023 (UTC)
- All except this one have a in them. They give the right result, given the units of the . This one seems to have magic until built into the 18 and 40. Gah4 (talk) 00:12, 2 September 2023 (UTC)
Conventional or electronic current
editClarification is needed in the excerpt below as to whether conventional or electronic current flow is implied:
"The potential is therefore called a back EMF. If the current is increasing, the voltage is positive at the end of the conductor through which the current enters and negative at the end through which it leaves, tending to reduce the current. If the current is decreasing, the voltage is positive at the end through which the current leaves the conductor, tending to maintain the current." Mgasilva (talk) 16:22, 12 August 2024 (UTC)
- Pretty much the only time electronic (that is, negative charges moving) current is used, is for vacuum tubes. Consider that some metals, such as iron, have a positive Hall coefficient, and so positive charge carriers. That is especially interesting for inductors. But the whole idea, is that it doesn't matter the sign of the charge carriers, except in vacuum tubes. Gah4 (talk) 18:43, 12 August 2024 (UTC)
- Conventional current by default. We do not need spoiler alerts, and we do not need warnings when we are using conventional current. Constant314 (talk) 18:54, 12 August 2024 (UTC)
wire inductance basic formulas
editFor straight wire ,I propose L= 4/pi3 x mu0/pi2 x l x ln(l/r) where l is wire length and r is radius For circular loop, L= 4/pi x mu0/pi2 x l x ln l/pi.r the skin effect factor for these formulas is square root of (1 + square root of delta / wire diameter ) delta is the depth of current penetration I have also formulas for their respective capacitance length and radius are in meters Leveugel (talk) 14:52, 15 May 2026 (UTC)
- Do you have a reference for that. We no longer add material to Wikipedia without including the reliably published sources, such as texbooks, etc. StarryGrandma (talk) 00:13, 16 May 2026 (UTC)
- Hello
- My sources are principally my measures and calculations.
- I am a hamradio ( F8SQD ) sorry Leveugel (talk) 06:51, 16 May 2026 (UTC)
- That would be WP:OR or original research. Wikipedia does not allow that. Constant314 (talk) 09:28, 16 May 2026 (UTC)
With the formulas in the article, the same wire of the example ( 10 m of 18 AWG ) has more self-inductance in straight shape ( 19.67 micro Henry ) than in circular loop shape ( 16.22 micro Henry ) ...
In reality ( measurements ) the circular loop is always superior in value to the straight wire... ( 14.16 micro Henry and 1.62 micro Henry respectively in this case ).Leveugel (talk) 13:34, 6 June 2026 (UTC)
The ratio between a circular loop and a straight wire self-inductance is equal to pi2 divided by the square of the velocity factor in the loop equal to ln l/a divided by ln l/pi.a...Leveugel (talk) 06:55, 9 June 2026 (UTC)
- You are trying to make an argument. That won't work for Wikipedia. You must have a reliable source. Constant314 (talk) 15:01, 6 June 2026 (UTC)
- WP:NOTFORUM. The talk page is to discuss specific improvements to the article. It is not a forum for speculative WP:OR. Constant314 (talk) 14:47, 9 June 2026 (UTC)