Osekovo is a village in Croatia.
Osekovo | |
|---|---|
Village | |
 Interactive map of Osekovo | |
| Country |  Croatia |
| County | Sisak-Moslavina County |
| Area | |
• Total | 34.0 km2 (13.1 sq mi) |
| Population (2021)[2] | |
• Total | 705 |
| • Density | 20.7/km2 (53.7/sq mi) |
| Time zone | UTC+1 (CET) |
| • Summer (DST) | UTC+2 (CEST) |
Population
editGeographical Location
editThe village of Osekovo is located in central‑eastern Croatia, within Sisak‑Moslavina County and administratively part of the Popovača municipality. The village lies at coordinates 45°31′ N and 16°37′ E, approximately 100 kilometers southeast of the capital, Zagreb.
Osekovo is situated in a low, flat plain within the Sava River basin, adjacent to wetlands and floodplain forests of the Lonjsko Polje Nature Park, one of the largest protected wetlands in Croatia. The surrounding environment features fertile agricultural land and rich biodiversity, including migratory birds and aquatic wildlife, making it part of the network of protected natural areas in the Sava River valley.[4]
References
edit- ↑ Register of spatial units of the State Geodetic Administration of the Republic of Croatia. Wikidata Q119585703.
- ↑ "Population by Age and Sex, by Settlements" (xlsx). Census of Population, Households and Dwellings in 2021. Zagreb: Croatian Bureau of Statistics. 2022.
- 1 2 3 "Osekovo (Popovača, Sisak-Moslavina , Croatia) - Population Statistics, Charts, Map, Location, Weather and Web Information". www.citypopulation.de. Retrieved 2025-11-10.
- ↑ "Posjetiteljski_centar_EN" (PDF).
45°31′N 16°37′E / 45.517°N 16.617°E
 | This Sisak-Moslavina County geography article is a stub. You can help Wikipedia by adding missing information. |