The 1824 United States presidential election in New York took place on November 11, 1824, as part of the 1824 United States presidential election.[1] The state legislature chose 36 representatives, or electors to the Electoral College, who voted for President and Vice President.
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November 11, 1824
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During this election, the Democratic-Republican Party was the only major national party, and 4 different candidates from this party sought the Presidency. New York cast 26 electoral votes for John Quincy Adams, 5 for William H. Crawford, 4 for Henry Clay and 1 for Andrew Jackson. John C. Calhoun received 29 votes for vice president and Nathan Sanford received 7 votes. This election marks the last time the New York State Legislature chose the state's electors as opposed to using some form of popular vote method.[2]
Results
edit| 1824 United States presidential election in New York[3] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Electoral votes | |||
| Democratic-Republican | John Quincy Adams | 26 | |||
| Democratic-Republican | William H. Crawford | 5 | |||
| Democratic-Republican | Henry Clay | 4 | |||
| Democratic-Republican | Andrew Jackson | 1 | |||
| Totals | 36 | ||||
See also
editReferences
edit- ↑ Hutchins, Stephen C., ed. (1879). Civil List and Forms of Government of the Colony and State of New York. Albany. p. 345.
- ↑ Moore, John L., ed. (1985). Congressional Quarterly's Guide to U.S. Elections (2nd ed.). Washington, D.C.: Congressional Quarterly, Inc. pp. 254–56.
- ↑ "1824 Electoral College Results". National Archives. Retrieved November 25, 2025.