Greenfield Township, Orange County, Indiana

(Redirected from Fargo, Indiana)

Greenfield Township is one of ten townships in Orange County, Indiana, United States. As of the 2020 census, its population was 746 and it contained 494 housing units.[1]

Greenfield Township
Location in Orange County
Location in Orange County
Coordinates: 38°26′45″N 86°30′39″W / 38.44583°N 86.51083°W / 38.44583; -86.51083
Country United States
State Indiana
CountyOrange
Government
  TypeIndiana township
Area
  Total
43.14 sq mi (111.7 km2)
  Land41.22 sq mi (106.8 km2)
  Water1.92 sq mi (5.0 km2)  4.45%
Elevation
673 ft (205 m)
Population
 (2020)
  Total
746
  Density18.1/sq mi (6.99/km2)
Time zoneUTC-5 (Eastern (EST))
  Summer (DST)UTC-4 (EDT)
ZIP codes
47118, 47140, 47175, 47432, 47454
Area codes812, 930
GNIS feature ID453352
Historical population
CensusPop.Note
18901,444
19001,383−4.2%
19101,167−15.6%
19201,058−9.3%
1930828−21.7%
19408634.2%
1950601−30.4%
1960459−23.6%
1970338−26.4%
198046938.8%
1990418−10.9%
200055933.7%
201073030.6%
20207462.2%
Source: US Decennial Census[2]

Geography

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According to the 2010 census, the township has a total area of 43.14 square miles (111.7 km2), of which 41.22 square miles (106.8 km2) (or 95.55%) is land and 1.92 square miles (5.0 km2) (or 4.45%) is water.[3]

Unincorporated towns

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Major highways

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Lakes

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  • Tucker Lake

School districts

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  • Paoli Community School Corporation

Political districts

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References

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